Answer:
k= [tex]\frac{-1}{240}[/tex]
Step-by-step explanation:
Given : [tex]\frac{1}{3k}+80 =\frac{1}{2k}+120[/tex].
To find : What does k =
Solution : We have given
[tex]\frac{1}{3k}+80 =\frac{1}{2k}+120[/tex].
On subtracting both sides by 80
[tex]\frac{1}{3k}=\frac{1}{2k}+120-80[/tex].
[tex]\frac{1}{3k}=\frac{1}{2k}+40[/tex].
On subtracting both sides by [tex]\frac{1}{2k}[/tex].
[tex]\frac{1}{3k}-\frac{1}{2k}= 40[/tex].
On taking common denominator
[tex]\frac{2-3}{6k}= 40[/tex].
[tex]\frac{-1}{6k}= 40[/tex].
k= [tex]\frac{-1}{240}[/tex].
Therefore, k= [tex]\frac{-1}{240}[/tex].
