Respuesta :

LammettHash
Assuming the matrix is

[tex]\mathbf A=\begin{bmatrix}-8&3\\-3&10\end{bmatrix}[/tex]

we have characteristic polynomial given by the equation

[tex]\det(\mathbf A-\lambda \mathbf I)=0\iff\begin{vmatrix}-8-\lambda&3\\-3&10-\lambda\end{vmatrix}=0[/tex]
[tex](-8-\lambda)(10-\lambda)-(-9)=0[/tex]
[tex]\lambda^2-2\lambda-71=0[/tex]

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