The average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeded 77. round to four decimal places.

Here, we first calculate the value of 't' and then go on calculating the probability that the t-value is more than calculated t-value, given the degree of freedom (d.f. = n-1). t.calc = (77-76)/(5/sqrt(100)) = 1/(1/2) = 2 P(x > 77) = P(t > 2, d.f. =99) = 0.0241= 2.41%

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priyankamittal483 priyankamittal483 · Answer 2 · 2022-07-14T10:39:34+02:00

The probability that the average score of the 100 golfers exceeded 77 is 2.41.

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An expression is a number, a variable, or a combination of numbers and variables and operation symbols

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Here, we first calculate the value of 't' and then go on calculating the probability that the t-value is more than calculated t-value, given the degree of freedom (d.f. = n-1). t.calc = (77-76)/(5/sqrt(100)) = 1/(1/2) = 2 P(x > 77) = P(t > 2, d.f. =99) = 0.0241= 2.41%

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