Im pretty the answer is 164 cm. not 124 cm.!!!
14 + 14 + 56 + 40 + 40 = 164
check in a calculator
Answer:
D. 164 [tex]cm^{2}[/tex]
Step-by-step explanation:
We have that the net includes three rectangles and two triangles.
So, the surface area of the net = area of 3 rectangles + area of 2 triangles.
Now, there are two rectangles having length 8 cm and width 5 cm.
So, the area of this rectangle = length × breadth = 8 × 5 = 40 [tex]cm^{2}[/tex]
Also, one rectangle has length 8 cm and width 7 cm.
So, the area of this rectangle = length × breadth = 8 × 7 = 56 [tex]cm^{2}[/tex]
Now, as there are two triangles having base length 7 cm and height 4 cm.
So, area of both of these triangles = [tex]2 \times \frac{1}{2} \times b \times h[/tex] = [tex]2 \times\frac{1}{2} \times 7 \times 4[/tex] =28 [tex]cm^{2}[/tex].
Therefore, the final area of the net = 40 + 40 + 56 + 28 = 164 [tex]cm^{2}[/tex].
