Answer:
The final volume of the sample of gas is 1170 L.
Explanation:
Initial volume of the gas =[tex]V_1= 500 mL= 0.5L[/tex]
Initial temperature of the gas =[tex]T_1= 150 K[/tex]
Final volume of the gas =[tex]V_2=?[/tex]
Final temperature of the gas =[tex]T_2=350 K[/tex]
Since, pressure and number of moles remains constant we can apply Charles law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
[tex]\frac{0.5 L\times 350 K}{150 K}=V_2[/tex]
[tex]V_2=1.16666 L=1166.66 mL\approx 1170 L[/tex]
The final volume of the sample of gas is 1170 L.
