The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of the rectangle in terms of w?
1. 2(5/2w) + w
2. 5/2w + w
3. 3w + 10/2
4. 6w + 5

Respuesta :

Answer:

Option 4 is correct

[tex]P=5+6w[/tex]

Step-by-step explanation:

Perimeter of a rectangle is given by:

[tex]P=2(l+w)[/tex]            ....[1]

where w be the width of the rectangle and l be the length of the rectangle.

As per the statement:

length of a rectangle is 5/2 units greater than twice its width.

⇒ [tex]l = \frac{5}{2}+ 2w[/tex] units

Substitute this in [1] we get;

[tex]P=2(\frac{5}{2}+ 2w+w)[/tex]

Combine like terms;

[tex]P=2(\frac{5}{2}+3w)[/tex]

Using distributive property: [tex]a\cdot (b+c) =a\cdot b+ a\cdot c[/tex]

[tex]P=5+6w[/tex]

Therefore, the perimeter of the rectangle in terms of w is [tex]P=5+6w[/tex] units