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there is a bus moving at 30.2 m/s and the bus must now jump a 50 foot gap in the freeway.if the interchange has a 5° incline how far can the bus travel and still land on the same vertical level after leaves the ramp? will the bus make it the 50 feet?

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feynman135
The bus won’t make it by a long shot if I did the math right.
I split the velocity into two components: vertical and horizontal, using trig. I then used a modified height formula to get that 2.63t-4.9t^2 = 0, t = 0.531639, x = 30.08*0.531639 = 16.16 meters before it falls into the ditch. Note that 2.63 = 30.2*sin(5) and 30.08 = 30.2*sin(5). I hope that made some sense!

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