A pelican flying drops a fish from a height of 8.1 m. The fish travels 9.3 m horizontally before it hits the ground. The pelican’s speed was

Respuesta :

Using kinematics: 8.1 = 1/2(9.8)(t^2),
t = 1.2857 s.
Horizontal distance x travelled is x = vhorizontal * t, so 9.3 = v*1.2857, or v= 7.233 m/s horizontally.

The pelican’s speed was 7.233 m/s horizontally.

What is horizontal launch?

The horizontal movement of the body corresponds to a Uniform Movement, that is, it has constant speed. During the parabolic fall, the only acceleration acting on the body is gravity, which is vertical and downward.

So making the calculus we have:

[tex]Horizontal \ distance * x = v * t\\ 8.1 = 1/2(9.8)(t^2)\\t = 1.2857 s\\9.3 = v*1.2857\\ v= 7.233 m/s[/tex]

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