contestada

At constant temperature, a sample of helium at 760. torr in a closed container was compressed from 5.00 l to 3.00 l, with no change in moles or temperature. what was the new pressure exerted by the helium on its container? 2280 torr 800. torr 15.0 torr 3800 torr 1270 torr

Respuesta :

Kalahira
At constant temperature and moles, the answer can simply becomes P1V1 = P2V2. The original sample is 760 torr and 5.00 l, and was then compressed to 3.00 l. (760 torr)(5.00 l ) = (3.00 l)(X torr), X = 1270 torr. The new pressure exerted by helium on its container is 1270 torr.

Otras preguntas