All scalar multiples of the vector [ 4, 5] makes the
line y = 5/4 x.
The matrix A of the orthogonal projection onto the line L is made of the
coordinates of the projections of the base trajectories i and j onto the line L
printed in columns.
The line L: y = 5/4*x
Orthogonal line passing over the point (1, 0): y = -4/5 *x + 4/5
Point of Intersection: (16/41, 21/41)
Projections: P(i) = 16/41 i + 21/41 j, P(j) = 16/41 i + 21/41 j
The matrix:
A = || 16/41..16/41||
......|| 16/41....16/41 ||
