Respuesta :
Finding the sample size for estimating a population proportion.
The formula is:
n = (z/m)^2 p~(1−p~)
where:
Z is the z value of the confidence level where 95% is equal to 1.96
M is the margin of error where 0.05
And p~ is the estimated value of the proportion where it is 0.50
Solution:
n = (1.96/0.05)^2 (0.5) (1-0.5)
= 1.536.64 (0.5) (0.5)
= 768.32 (0.5)
= 384.16
This is the minimum sample size, therefore we should round it up to 385. The answer is letter c.
The formula is:
n = (z/m)^2 p~(1−p~)
where:
Z is the z value of the confidence level where 95% is equal to 1.96
M is the margin of error where 0.05
And p~ is the estimated value of the proportion where it is 0.50
Solution:
n = (1.96/0.05)^2 (0.5) (1-0.5)
= 1.536.64 (0.5) (0.5)
= 768.32 (0.5)
= 384.16
This is the minimum sample size, therefore we should round it up to 385. The answer is letter c.
This is the minimum sample size, therefore we should round it up to 385.
Finding the sample size for estimating a population proportion.
What is the formula for sample size?
The formula of sample size
n = (z/m)^2 p~(1−p~)
Z is the z value of the confidence level where 95% is equal to 1.96
M is the margin of error where 0.05
And p~ is the estimated value of the proportion where it is 0.50
Solution:
n = (1.96/0.05)^2 (0.5) (1-0.5)
= 1.536.64 (0.5) (0.5)
= 768.32 (0.5)
= 384.16
This is the minimum sample size, therefore we should round it up to 385.
Therefore, The correct answer is letter c.
To learn more about sample size visit:
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