In fruit flies, the gene for red eyes (R) is dominant and the gene for sepia eyes (r) is recessive. If two red-eyed heterozygous flies (Rr) mate together, what are the possible genotypes of their offspring? (Hint: You many want to complete a Punnett square.)

RR and Rr
Rr only
RR and rr
RR, Rr, and rr

Respuesta :

The ratio of the possible genotypes of their offsprings are: 1 RR : 2 Rr : 1 rr

The punnet square is a diagram in a square form that is used to forecast the possible genotypes of offspring during breeding experiments.

From the given information:

  • Gene for red eyes = R
  • Gene for sepia eyes = r

If two heterozygous flies Rr mate together, the number of the possible genotypes of their offspring can be determined by using the punnet square.

            R        r

R          RR     Rr

r           Rr      rr

Therefore, the genotypes are:

  • 1 RR → a dominant gene for red eye
  • 2 Rr → heterozygous gene for red eye
  • 1 rr   → recessive gene for sepia eye

Therefore, we can conclude that the ratio of the possible genotypes of their offsprings are: 1 RR : 2 Rr : 1 rr

Learn more about monohybrid crossing here:

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