Respuesta :
Answer:
B. Both are irrational
Step-by-step explanation:
We know that,
Rational numbers are the numbers that can be written in the form [tex]\frac{p}{q}[/tex], where q≠0.
Irrational numbers are the numbers which are not rational i.e. cannot be written in the form [tex]\frac{p}{q}[/tex], where q≠0.
According to our question,
A = [tex]\sqrt{3} +\sqrt{2}[/tex], this cannot be simplifies further and can never be written as [tex]\frac{p}{q}[/tex].
Similarly, B = [tex]\sqrt{3} +\sqrt{6}[/tex], cannot be simplified further into [tex]\frac{p}{q}[/tex] form.
Hence, both the numbers in A and B are irrational numbers.
