Respuesta :
standard deviation(σ[tex]_{x} [/tex]) = √V(X) = 10
Therefore, variance of X. V(X) = 10² = 100
Variance of aX is given by,
V(aX) = a²V(X)
Therefore, variance of 3X will be,
V(3X) = 3²V(X) = 9(100) = 900
Therefore, standard deviation of 3X is,
σ[tex]_{3x} [/tex] = √V(3X) = √900 = 30
Therefore, variance of X. V(X) = 10² = 100
Variance of aX is given by,
V(aX) = a²V(X)
Therefore, variance of 3X will be,
V(3X) = 3²V(X) = 9(100) = 900
Therefore, standard deviation of 3X is,
σ[tex]_{3x} [/tex] = √V(3X) = √900 = 30
The 3x has the standard deviation should be equivalent to 30.
Given that
- X represents the normal random variable.
- It contains a standard deviation of 10.
So, the 3x should be
= 3 × standard deviation
= 3 × 10
= 30
Therefore we can conclude that The 3x has the standard deviation should be equivalent to 30.
Learn more about the standard deviation here: brainly.com/question/16555520
