Respuesta :
Answer:
D) SO3
Explanation:
The correct empirical formula for this sulfur oxide is SO3. To determine this, assume 100g of the compound. This gives 40g of S and 60g of O. Next, divide each of these masses by the molar mass of each. 40/32=1.25mol of S and 60/16 = 3.75 mol of O. Finally, keep this ratio and reduce by dividing by the lower number. 3.75/1.25 = 3. Sulfur and oxygen combine in a 1:3 ratio.