A geometric sequence is defined by the equation an = (4)3 − n. part
a.what are the first three terms of the sequence? (1 point) part
b.what is the value of r? part
c.what is the value of a12?
a. an=4^(3-n) a1= 4^(3-1) = 4^2 = 16 a2= 4^(3-2) =4^1 = 4 a3= 4^(3-3) = 4^0 = 1 b. r= 1/4 (you can see from what I prove in the picture or from part a an= a1r^(n-1) 4 = 16(r)^(2-1) 4 = 16(r) so r = 4/16 = 1/4 c. a12=a1r^(n-1) =16(1/4)^(12-1) =16(1/4)^11 =16/ 4^11 =16/4194304 =3.81*10^(-5)
