Respuesta :
What would make finding the answer a bit easier, is converting them into improper fractions. You would turn that first fraction to [tex] \frac{-9}{4} [/tex] and the second fraction to [tex] \frac{-3}{2} [/tex]. (You are dividing a negative by a negative, therefore, your answer would be a positive.
Let's follow the procedure of keeping, switching, and flipping. You keep the first improper fraction, switch the division sign to a multiplication sign, and flip the second fraction. That would make it : [tex] \frac{-9}{4} [/tex] ×[tex] \frac{-2}{3} [/tex].
You multiply the 9 and the 2, you get 18. You multiply the 3 and the 4, you get 12. That makes it [tex] \frac{18}{12} [/tex]. This, converted to a mixed fraction, makes 1[tex] \frac{6}{12} [/tex]., which is the same as 1[tex] \frac{1}{2} [/tex]. Your answer is the SECOND CHOICE.
Let's follow the procedure of keeping, switching, and flipping. You keep the first improper fraction, switch the division sign to a multiplication sign, and flip the second fraction. That would make it : [tex] \frac{-9}{4} [/tex] ×[tex] \frac{-2}{3} [/tex].
You multiply the 9 and the 2, you get 18. You multiply the 3 and the 4, you get 12. That makes it [tex] \frac{18}{12} [/tex]. This, converted to a mixed fraction, makes 1[tex] \frac{6}{12} [/tex]., which is the same as 1[tex] \frac{1}{2} [/tex]. Your answer is the SECOND CHOICE.
[tex]-2 \frac{1}{4} :(-1 \frac{1}{2} )= \\ \\ = -\frac{9}{4} : (- \frac{3}{2} ) = \\ \\ = - \frac{9}{4} \times (- \frac{2}{3} ) = \\ \\ = \frac{18}{12} = \\ \\ = \frac{9}{6} = \\ \\ = \frac{3}{2} = 1 \frac{1}{2}
[/tex]
Obs.
(-) × (-) = +
Obs.
(-) × (-) = +