Respuesta :
We know that one container contains [tex]1 \frac{7}{8} [/tex] and the second container contains [tex]5 \frac{3}{4} [/tex]. To find how many more quarts of water the second container holds than the first one, we do:
[tex]5 \frac{3}{4} -1 \frac{7}{8}= [/tex] ←Make them have common denominator
[tex]5 \frac{6}{8}-1 \frac{7}{8=} [/tex] ←Make them into improper fraction
[tex] \frac{46}{8}- \frac{15}{8}=[/tex] ←Subtract them
[tex] \frac{31}{8}= [/tex] ←Simplify
[tex]3 \sqrt[7]{8} [/tex] ←That's your answer
[tex]5 \frac{3}{4} -1 \frac{7}{8}= [/tex] ←Make them have common denominator
[tex]5 \frac{6}{8}-1 \frac{7}{8=} [/tex] ←Make them into improper fraction
[tex] \frac{46}{8}- \frac{15}{8}=[/tex] ←Subtract them
[tex] \frac{31}{8}= [/tex] ←Simplify
[tex]3 \sqrt[7]{8} [/tex] ←That's your answer
Well first,you have to convert 17/8 to a mixed number.You have to do that because it is a improper fraction.17/8 as a mixed is 2 1/8.Then you subtract 5 3/4 from 2 1/8.
After all the work you should get 3 5/8
After all the work you should get 3 5/8