Respuesta :

cpat17
0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18

Answer:

Coefficient of sliding friction is 0.33.

Explanation:

The force of sliding friction is proportional to the normal force. It is given by:

[tex]F_s=\mu _sF_N[/tex]

The normal force of the box is equal to its weight as the force in the vertical direction is balanced.

[tex]F_N= 18N[/tex]

[tex]F_s= 6.0N[/tex] (given)

Thus, the coefficient of sliding friction is:

[tex] \mu _s=\frac{F_s}{F_N}=\frac{6.0}{18} = 0.33[/tex]

Thus, the coefficient of sliding friction is 0.33.