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Which of the following describes the solution to the equation √c^2+2c-4=√1-2c?

– 5 is an extraneous solution, and 1 is a true solution.
– 5 is a true solution, and 1 is an extraneous solution.
Both –5 and 1 are true solutions.
Both –5 and 1 are extraneous solutions.

Respuesta :

carlosego
√c^2+2c-4=√1-2c
 raising both members to the square
 c^2+2c-4=1-2c
 rewriting
 c^2+4c-5=0
 factoring
 (c+5)*(c-1)=0
 the solutions for this case re
 c=-5
 c=1
 the answer is 
 Both –5 and 1 are true solutions

Answer:

both 5 and 1 are true

Step-by-step explanation:

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