Respuesta :
percent composition by mass of oxygen =
((16.0*6)/(40.1+2*(14.0+16.0*3)))*100%
= 58.5%
therefore, the answer is D
((16.0*6)/(40.1+2*(14.0+16.0*3)))*100%
= 58.5%
therefore, the answer is D
Answer:
A. 9.8%
Explanation:
Percentage Composition = (Mass of element / Mass of compound) * 100
Mass of oxygen = 16g
Molar mass of Ca(NO3)2
Where;
Ca = 40
N = 14
O =16
Molar mass = 40 + 2[14 + 3(16)] = 164
Substituting into the formular;
Percentage composition = (16 / 164) * 100
Percentage Composition = 0.0975 * 100
Percentage Composition = 9.75% ≈ 9.8 %
Correct option = A