According to the given diagram,
Coordinates of A(5,2),B(12,-5) and D(2,-1)
d(AB)=[tex] \sqrt{\left ( x2-x1 \right )^2+\left ( y2-y1 \right )^2} [/tex]
d(AB)=[tex] \sqrt{\left ( 12-5 \right )^2+\left ( -5-2 \right )^2} [/tex]
d(AB)=[tex] \sqrt{\left (7 \right )^2+\left (-7\right )^2} [/tex]
d(AB) = 9.899 = 9.9 units
d(AD)=[tex] \sqrt{\left ( 2-5 \right )^2+\left ( -1-2 \right )^2} [/tex]
d(AD)=[tex] \sqrt{\left ( -3\right )^2+\left ( -3 \right )^2} [/tex]
d(AD) = 4.24 units
Area of rectangle (ABCD) = (AB)(AD)
Area of rectangle (ABCD)=(9.9)(4.24) = 41.976 sq.units
