Respuesta :
if you notice in the graph, you can pick any two points to get the slope of it, hmm let's say we use 0, -3 and 6,1, which are there in the picture,
[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 0 &,& -3~) % (c,d) &&(~ 6 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-3)}{6-0}\implies \cfrac{1+3}{6-0}\implies \cfrac{4}{6}\implies \cfrac{2}{3}[/tex]
[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 0 &,& -3~) % (c,d) &&(~ 6 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-3)}{6-0}\implies \cfrac{1+3}{6-0}\implies \cfrac{4}{6}\implies \cfrac{2}{3}[/tex]
if i am reading what you wrote correctly then you are asking for the slope of the line that passes through coordinate points (0/-3),(6,1)
so slope is defined by m=y2-y1/x2-x1 therefore we have;
(1-(-3))/(6-0)=4/6=2/3
so the answer to your question is the slope =2/3
Hope my explanation and answer helped you! If you have any questions please don't hesitate to ask! Please rate my answer as it will help me a lot as well! Thank you so much!
so slope is defined by m=y2-y1/x2-x1 therefore we have;
(1-(-3))/(6-0)=4/6=2/3
so the answer to your question is the slope =2/3
Hope my explanation and answer helped you! If you have any questions please don't hesitate to ask! Please rate my answer as it will help me a lot as well! Thank you so much!