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1. Simplify using only positive exponents: (2t)^-6

2. Simplify using only positive exponents: (w^-2j^-4)^-3( j^7j^3)

Respuesta :

anchitthawi

[tex]1. \: ( {2t})^{ - 6} = (\frac{1}{2t} ) ^{6} \\ = \frac{1}{ ({2t)}^{6} } = \frac{1}{ {2}^{6} {t}^{6} } = \frac{1}{64 {t}^{6} } [/tex]
[tex]2. \: ( {w}^{ - 2} {j}^{ - 4} )^{ - 3} ( {j}^{7} {j}^{ 3} ) \\ = ( {w}^{6} {j}^{12} )( {j}^{7} {j}^{3} ) \\ = {w}^{6} {j}^{12 + 7 + 3} \\ = {w}^{6} {j}^{22} [/tex]

Answer:

Q2.(w−2j−4)−3j7j3

=j22w6

Q1.(2t)−6

=(2t)−6

=

1

2t*2t*2t*2t*2t*2t

=

1

64t6

Step-by-step explanation:

Hope I helped

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