Respuesta :
Given from question
a = 1
an = 25
b = a₂ - a = 3 - 1 = 2
Asked from question
Sn
Solution
The general formula for finding the sum of arithmetic series is
Sn = n/2 (a + an)
Because we don't know yet the value of n, we should find it first, with this,
an = a + d(n - 1)
25 = 1 + 2(n - 1)
25 = 1 + 2n - 2
25 = 2n - 1
2n = 24
n = 12
After finding the value of x, calculate the sum of series by the formula I mentioned above
Sn = n/2 (a + an)
S₁₂ = 12/2 (1 + 25)
S₁₂ = 6 (26)
S₁₂ = 156
The sum of the series is 156
a = 1
an = 25
b = a₂ - a = 3 - 1 = 2
Asked from question
Sn
Solution
The general formula for finding the sum of arithmetic series is
Sn = n/2 (a + an)
Because we don't know yet the value of n, we should find it first, with this,
an = a + d(n - 1)
25 = 1 + 2(n - 1)
25 = 1 + 2n - 2
25 = 2n - 1
2n = 24
n = 12
After finding the value of x, calculate the sum of series by the formula I mentioned above
Sn = n/2 (a + an)
S₁₂ = 12/2 (1 + 25)
S₁₂ = 6 (26)
S₁₂ = 156
The sum of the series is 156
Answer:
Sum of the arithmetic series of odd numbers 1 + 3 + 5 + ... + 25 is 169 .
Step-by-step explanation:
Formula of airthmetic series
[tex]a_{n}=a_{1}+(n-1)d[/tex]
[tex]S_{n} = \frac{n(a_{1}+a_{n})}{2}[/tex]
Where n is the nth term , [tex]a_{n}[/tex] is the nth term , d is the common difference and [tex]a_{1}[/tex] is the first term .
As the airthmetic series given in the question .
1 + 3 + 5 + ... + 25
[tex]a_{1}= 1[/tex]
[tex]a_{2}= 3[/tex]
[tex]d=a_{2}-a_{1}[/tex]
d = 3 - 1
d = 2
[tex]a_{n}= 25[/tex]
Put all the values in the formula
[tex]25=1+(n-1)2[/tex]
25 - 1 = 2n - 2
24 + 2 = 2n
26 = 2n
[tex]n = \frac{26}{2}[/tex]
n = 13
Now put the values in the another formula
[tex]S_{n} = \frac{13\times (1+25)}{2}[/tex]
[tex]S_{n} = \frac{13\times (26)}{2}[/tex]
[tex]S_{n} = 13\times 13[/tex]
[tex]S_{n} = 169[/tex]
Therefore the sum of the arithmetic series of odd numbers 1 + 3 + 5 + ... + 25 is 169 .