Respuesta :
Melanie: (2010, 48) and (2013, 59)
Equation will be
y = (59-48)/(2013-2010) * (x - 2010) + 48
>> y = (11/3) * (x - 2010) + 48
>> y = (11/3)x - (11/3)*2010 + 48
>> y = (11/3)x - 7370 + 48
>> y = (11/3)x - 7322
Tracy: (0, 48) and (3, 59)
Equation will be
y = (59-48)/(3-0) * (x - 0) + 48
>> y = (11/3) * x + 48
>> y = (11/3)x + 48
The slopes of both the equations are same, but y-intercept are different. Because Melanie used actual years (variable x), whereas Tracy used years since 2010.
Equation will be
y = (59-48)/(2013-2010) * (x - 2010) + 48
>> y = (11/3) * (x - 2010) + 48
>> y = (11/3)x - (11/3)*2010 + 48
>> y = (11/3)x - 7370 + 48
>> y = (11/3)x - 7322
Tracy: (0, 48) and (3, 59)
Equation will be
y = (59-48)/(3-0) * (x - 0) + 48
>> y = (11/3) * x + 48
>> y = (11/3)x + 48
The slopes of both the equations are same, but y-intercept are different. Because Melanie used actual years (variable x), whereas Tracy used years since 2010.
A trend line is represented as linear function.
The relationships between the girls' equation are:
- The equations will have the same slope
- The equations will have different y-intercepts
The points are given as:
[tex]\mathbf{Melanine = \{(2010,48),(2013,59)\}}[/tex]
[tex]\mathbf{Tracy = \{(0,48),(3,59)\}}[/tex]
Because the points represent the same measure, their equations will have the same slope. The proof is as follows.
The slope of a line is;
[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]
So, we have:
[tex]\mathbf{Melanine = \frac{59- 48}{2013- 2010} = \frac{9}{3} = 3}[/tex]
[tex]\mathbf{Tracy= \frac{59- 48}{3- 0} = \frac{9}{3} = 3}[/tex]
The above shows that, the both equations have the same slope (3)
However, the equations will have different y-intercepts
The y-intercept is when x = 0
From Tracy's points, y = 48 when x = 0
For Melanine's points: y = 48 (same as Tracy's) when x = 2010 (a different x-value)
Read more about trend lines at:
https://brainly.com/question/22722918