Melanie and Tracy are each finding the equation of the trend line that fits the data in the table below. Melanie uses the ordered pairs (2010, 48) and (2013, 59) to find her equation. Tracy defines x as the number of years since 2010 and uses the ordered pairs (0, 48) and (3, 59) to find her equation. How will the two girls’ equations compare?

Respuesta :

Melanie (2010, 48) and (2013, 59)
Equation will be
y = (59-48)/(2013-2010) * (x - 2010) + 48
>> y = (11/3) * (x - 2010) + 48
>> y = (11/3)x - (11/3)*2010 + 48
>> y = (11/3)x - 7370 + 48 
>> y = (11/3)x - 7322 

Tracy:  (0, 48) and (3, 59)
Equation will be
y = (59-48)/(3-0) * (x - 0) + 48
>> y = (11/3) * x + 48
>> y = (11/3)x + 48 

The slopes of both the equations are same, but y-intercept are different. Because Melanie used actual years (variable x), whereas Tracy used years since 2010.

A trend line is represented as linear function.

The relationships between the girls' equation are:

  • The equations will have the same slope
  • The equations will have different y-intercepts

The points are given as:

[tex]\mathbf{Melanine = \{(2010,48),(2013,59)\}}[/tex]

[tex]\mathbf{Tracy = \{(0,48),(3,59)\}}[/tex]

Because the points represent the same measure, their equations will have the same slope. The proof is as follows.

The slope of a line is;

[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]

So, we have:

[tex]\mathbf{Melanine = \frac{59- 48}{2013- 2010} = \frac{9}{3} = 3}[/tex]

[tex]\mathbf{Tracy= \frac{59- 48}{3- 0} = \frac{9}{3} = 3}[/tex]

The above shows that, the both equations have the same slope (3)

However, the equations will have different y-intercepts

The y-intercept is when x = 0

From Tracy's points, y = 48 when x = 0

For Melanine's points: y = 48 (same as Tracy's) when x = 2010  (a different x-value)

Read more about trend lines at:

https://brainly.com/question/22722918