Respuesta :
Answer : The actual yield of hydrogen gas is, 3.618 grams
Explanation : Given,
Given moles of [tex]Li[/tex] = 3.75 moles
Molar mass of [tex]H_2[/tex] = 2 g/mole
Now we have to calculate the moles of [tex]H_2[/tex].
The balanced chemical reaction will be,
[tex]2Li+2HF\rightarrow 2LiF+H_2[/tex]
From the given balanced reaction, we conclude that
As, 2 moles of [tex]Li[/tex] react to give 1 mole of [tex]H_2[/tex]
So, 3.75 moles of [tex]Li[/tex] react to give [tex]\frac{3.75}{2}=1.875[/tex] moles of [tex]H_2[/tex]
Now we have to calculate the mass of [tex]H_2[/tex].
[tex]\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2[/tex]
[tex]\text{Mass of }H_2=(1.875mole)\times (2g/mole)=3.75g[/tex]
The theoretical yield of [tex]H_2[/tex] is, 3.75 grams
Now we have to calculate the actual yield of [tex]H_2[/tex].
[tex]\%\text{ yield of }H_2=\frac{\text{Actual yield of }H_2}{\text{Theoretical yield of }H_2}\times 100[/tex]
[tex]96.5=\frac{\text{Actual yield of }H_2}{3.75g}\times 100[/tex]
[tex]\text{Actual yield of }H_2=3.618g[/tex]
Therefore, the actual yield of hydrogen gas is, 3.618 grams
