The given expression is
[tex] 3 \sqrt{750}+ 3 \sqrt{2058}-3 \sqrt{48} [/tex]
We have to check out the factors of 750, 2058 and 48
[tex] 3 \sqrt{5^2 *30 } +3 \sqrt{7^2 *42} -3 \sqrt{4^2 *3} [/tex]
And square root of a perfect square number is the number itself.
That is
Square root of 25 is 5, square root of 49 is 7 and square root of 16 is 4.
So we will get
[tex] 3*5 \sqrt{30} +3*7 \sqrt{42} - 3*4 \sqrt{3}
\\
= 15 \sqrt{30} + 21 \sqrt{42} -12 \sqrt{3} [/tex]
