contestada

How many molecules are present in 936 g of glucose (C6H12O6)?
(The molar mass of glucose = 180.16 g/mol.)
A)3.14 × 1024 molecules
B)3.129 × 1024 molecules
C)3.1229 × 10-25 molecules
D)5.195 × 1023 molecules

Respuesta :

tylerrmitchell2
The Answer would be A. 3.14*1024 molecules.

Answer : The correct option is, (B) [tex]3.129\times 10^{24}[/tex]

Explanation :

First we have to calculate the moles of glucose.

[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{936g}{180.16g/mole}=5.195mole[/tex]

Now we have to calculate the number of molecules present in glucose.

As we know that,

1 mole of a substance contains [tex]6.022\times 10^{23}[/tex] number of molecules.

So, 5.195 mole of a substance contains [tex]5.195\times (6.022\times 10^{23})=31.286\times 10^{23}=3.129\times 10^{24}[/tex] number of molecules.

Therefore, the correct option is, (B) [tex]3.129\times 10^{24}[/tex]