Respuesta :
Answer:
[tex]x^2=y+16[/tex]
[tex]4y-1=7x[/tex]
Step-by-step explanation:
The condition says:
The square of first number is equal to the sum of the second number and 16:
Lets say that the first number is 'x' and the second number is 'y'. So the square of 'x' is [tex]x^2[/tex] and that is equal to the sum of second number i.e y and 16:
[tex]x^2=y+16[/tex]
Second condition says that:
The difference of 4 times the second number and 1 is equal to the first number multiplied by 7:
4 times the second number is [tex]4y[/tex] and difference of 1 is:
[tex]4y-1[/tex]
and this is equal to 7 times the first number: [tex]7\times x[/tex]
[tex]4y-1=7x[/tex]
So the two equations are:
[tex]x^2=y+16[/tex]
[tex]4y-1=7x[/tex]
