Respuesta :
Answer:
45 ft² will be blue
Explanation:
1- getting the area of the wall:
area of the rectangle can be calculated as follows:
area = length * width
we are given that:
length = [tex]16 \frac{1}{5} [/tex] ft
width = [tex]8 \frac{1}{3} [/tex] ft
Now, substituting in the above rule, we can get the area as follows:
area = [tex]16 \frac{1}{5} [/tex] * [tex]8 \frac{1}{3} [/tex] = 135 ft²
2- getting the area that would be pained blue:
We are given that [tex] \frac{1}{3} [/tex] of the area of the room would be painted blue, this means that:
area of blue = [tex] \frac{1}{3} [/tex] * area of room
area of blue = [tex] \frac{1}{3} [/tex] * 135
area of room = 45 ft²
Hope this helps :)
45 ft² will be blue
Explanation:
1- getting the area of the wall:
area of the rectangle can be calculated as follows:
area = length * width
we are given that:
length = [tex]16 \frac{1}{5} [/tex] ft
width = [tex]8 \frac{1}{3} [/tex] ft
Now, substituting in the above rule, we can get the area as follows:
area = [tex]16 \frac{1}{5} [/tex] * [tex]8 \frac{1}{3} [/tex] = 135 ft²
2- getting the area that would be pained blue:
We are given that [tex] \frac{1}{3} [/tex] of the area of the room would be painted blue, this means that:
area of blue = [tex] \frac{1}{3} [/tex] * area of room
area of blue = [tex] \frac{1}{3} [/tex] * 135
area of room = 45 ft²
Hope this helps :)