Qualitatively the momentum is the amount of motion contained in the body.
Quantitatively momentum is the product of mass and velocity of the body.
Mathematically momentum= mass×velocity
i.e p=m×v
where p denotes the momentum.
As per the question the initial velocity of the particle is given as [u]=60 m/s
The final velocity of the particle is given as [v]=30 m/s
Let the mass of the particle is m kg
The initial momentum [tex]p_{1} =m*u[/tex]
=60m kg m/s
the final momentum [tex]p_{2} =m*v[/tex]
=30m kg m/s
Hence the change in momentum is given as -
[tex]p_{2} -p_{1} =[30m -60m] kg m/s[/tex]
= -30m kg m/s
Here the minus sign indicates the loss of momentum
Hence the momentum is decreased by twice as the velocity is decreased by twice.
In general if velocity is decreased by m times ,then the momentum is decreased by m times also.
