[tex]\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad
\begin{cases}
A=\textit{accumulated amount}\to &2129.55\\
P=\textit{original amount deposited}\to& \$1950\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
t=years
\end{cases}
\\\\\\
2129.55=1950(1+0.065t)\implies \cfrac{2129.55}{1950}=1+0.065t
\\\\\\
\cfrac{2129.55}{1950}-1=0.065t\implies \cfrac{\frac{2129.55}{1950}-1}{0.065}=t[/tex]
