Unattached earlobes are dominant to attached earlobes. Cleft chin is dominant to no cleft. Parents that are heterozygous for both traits are crossed. Determine the genotype of the following offspring.

E= unattached earlobes
e= attached earlobes
Heterozygous means a dominant and non dominant trait so both parents have Ee. By using a punnet square you can determine the genotype of their offspring will be:
EE-25% chance
Ee-50%chance
ee-25% chance

Answer Link

aliasger2709 aliasger2709 · Answer 2 · 2022-01-27T17:48:16+01:00

The characters that are visible on the outer surface is called phenotype and the characters coded by the genes are called genotypes. The gene having the allele for the recessive and the dominant trait together is said to be heterozygous.

a) 9:16 b) 3:16 c) 3:16 d) 1:16 is the ratio of the genotypes of the offspring.

How to determine the genotype?

The alleles for the traits are given as:

The alleles for the Cleft chin = CC
The alleles for no Cleft chin = cc
The alleles for the unattached earlobes = EE
The alleles for the attached earlobes = ee
Parents with heterozygous trait = CcEe

See the attached image below for the Punnett square of the cross.

From the cross the ratios are:

Unattached earlobes and cleft chin = 9:16
Unattached earlobes and no cleft = 3:16
Attached earlobes and cleft chin = 3:16
Attached earlobes and no cleft = 1:16

Therefore, the genotype is 9:3:3:1.

Learn more about dihybrid cross here:

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