Respuesta :
According to Ohm's Law:
[tex]I = \frac{V}{R} [/tex]
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.
[tex]I = \frac{V}{R} [/tex]
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.
When the voltage is constant and the resistance is doubled then the current will drop to half of its original value.
What is electric current?
The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.
The given data in the problem is;
R₂=2R₁
I=?
V₂=V₁
From the ohm's law;
[tex]\rm I = \frac{V}{R} \\\\\[/tex]
V is the voltage
I am the current
R is the resistance
Current is directly proportional to Voltage and indirectly proportional to Resistance, as you can see above.
This indicates that as the voltage rises, the current rises, whereas as the resistance rises, the current falls.
So, in your example, if the voltage remains constant but the resistance doubles, the current will be cut in half.
As a result, the answer to your question is 2. The current will be reduced to half its original value.
From the given conditions;
[tex]\rm I_1 = \frac{V_1}{R_1}\\\\\ \rm I_2 = \frac{V_2}{R_2} \\\\ I_2 = \frac{V_2}{2R_1} \\\\\ I_2 = \frac{I_1}{2}[/tex]
Hence when the voltage is constant and the resistance is doubled then the current will drop to half of its original value.
To learn more about the electric current refer to the link;
brainly.com/question/7643273
