A leaky pool loses 2 1/4 inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water in the pool over 5 days.

Jermaine’s Solution Mildred’s Solution

5(-2 1/4) 5(-2 1/4)
5(-2 -1/4) 5(-2 -1/4)
-10 -1/4 -10 -5/4
-10 1/4 -11 1/4

Which describes the reasoning used to determine whose solution is correct?

A. Jermaine is correct because -10 -1/4 equals -10 1/4.
B.Jermaine is correct because he distributed 5 correctly.
C.Mildred is correct because she multiplied 5 by –2 but not by -1/4.
D.Mildred is correct because she distributed 5 correctly.




Respuesta :

Mildred's solution is correct.

5(-2 1/4) = 5(-2 + -1/4) = 5(-2) + 5(-1/4) = -10 + -5/4 = -10 + -1 1/4 = -11 1/4

Answer: D. Mildred is correct because she distributed 5 correctly.

Step-by-step explanation:

Since, the loss of water in one day = [tex]2\frac{1}{4}\text{ inches}[/tex]

⇒ The loss of water in 5 days = [tex]5(2\frac{1}{4})\text{ inches}[/tex]

⇒ The loss can be written with negative sign,

Thus, the expression that shows the changes in quantity of water in 5 days,

[tex]-5(2\frac{1}{4})[/tex]

[tex]=-5(2+\frac{1}{4})[/tex]

[tex]=5(-2-\frac{1}{4})[/tex]

[tex]=-10-\frac{5}{4}[/tex]

[tex]=-10-1\frac{1}{4}[/tex]

[tex]=-10-1-\frac{1}{4}[/tex]

[tex]=-11-\frac{1}{4}[/tex]

[tex]=-11\frac{1}{4}[/tex]

Since, the above steps are similar to that of Mildred's solution,

Mildred is correct.

Also, By the above explanation it is clear that jermaine incorrectly distribute 5 in his third steps.

⇒ Option D is correct.