Respuesta :
[tex]\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 9 &,& 8~)
% (c,d)
&B&(~ -1 &,& -2~)
\end{array}\qquad
% coordinates of midpoint
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-1+9}{2}~~,~~\cfrac{-2+8}{2} \right)\implies \left( \cfrac{8}{2}~~,~~\cfrac{6}{2} \right)\implies (4~~,~~3)[/tex]
Answer:
D. (4,3)
Explanation:
The endpoints of the line are given as (9,8) and (-1,-2)
1- Computing the x-coordinate of the midpoint:
Xmidpoint = (x1+x2) / 2 = (9+-1)/2 = 8/2 = 4
2- Computing the y-coordinate of the midpoint:
Ymidpoint = (y1+y2) / 2 = (8+-2) / 2 = 6/2 = 3
Based on the above, the midpoint is (4,3)
Hope this helps :)
D. (4,3)
Explanation:
The endpoints of the line are given as (9,8) and (-1,-2)
1- Computing the x-coordinate of the midpoint:
Xmidpoint = (x1+x2) / 2 = (9+-1)/2 = 8/2 = 4
2- Computing the y-coordinate of the midpoint:
Ymidpoint = (y1+y2) / 2 = (8+-2) / 2 = 6/2 = 3
Based on the above, the midpoint is (4,3)
Hope this helps :)