An isosceles triangle has area of 125 ft. If the base is 16 ft, what is the length of each leg? Round your answer to the nearest tenth

Hey there! :D

Area= 1/2*base*height

We know the area and the base. We will solve for height.

125= 1/2*16*h

Divide both sides by 2.

62.5= 16*h

Divide both sides by 16.

h=3.90625

Round to the nearest tenth.

h=3.9 <== the 9 is in the tenth place.

I hope this helps!
~kaikers

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shubhamsinha3013 shubhamsinha3013 · Answer 2 · 2022-05-12T11:54:01+02:00

The length of each leg of an isosceles triangle is 17.55 ft.

Isosceles triangle

An isosceles triangle is a triangle with two sides of equal length in geometry. It is sometimes stated as having exactly two equal-length sides, and other times as having at least two equal-length sides.

Area = bh/2

Where b is the base and h is the height of triangle.

How to find the length of each leg?

First, find the height of the triangle

Given isosceles triangle has an area of 125 ft. If the base is 16 ft.

Let the height be h

then,

(1/2)(16)h = 125

h = 125/8

h = 15.625

Now find the length of the leg

We know the perpendicular at base of an isosceles triangle divide triangle in a right triangle and h is the length of the perpendicular.

Let the leg is S.

then

S²= (16/2)² + (15.625)²

S² = 64+244.14

S² = 308.14

S = 17.55

Two sides of the isosceles triangle are equal.

Hence, the length of each leg is 17.55 ft.

Learn more about triangles here: https://brainly.com/question/2773823?referrer=searchResults

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