Two mice are heterozygous for albinism (aa) . the dominant allele (a) codes for normal pigmentation, and the recessive allele (a) codes for no pigmentation. what percentage of their offspring would have an albino phenotype?
25% because in a punnet square there would be one homozygous (AA) genotype for normal pigmentation, two heterozygous (As) genotypes for normal pigmentation and one homozygous (aa) genotype for albinisim.
