Answer:
Last term is 1,527,890.
Step-by-step explanation:
In this question a geometric series has been given with
first term A = 23
6th term = 1,358,127
Number of terms n = 6
we have to calculate the sum of this geometric series
we know [tex]T_{n}=a(r)^{n-1}[/tex]
[tex]T_{6}=23.(r)^{6-1}=1358,127[/tex]
[tex]r^{5}=\frac{1358127}{23}=59049[/tex]
[tex]r = 59049^{\frac{1}{5} }[/tex]
r = 9
Now we know the formula to sum a geometric series is
[tex]S=a.\frac{r^{n-1} }{r-1}[/tex]
S = 23 × [tex]\frac{(9^{6-1)} }{(9-1)}[/tex]
S = 23 × [tex]\frac{(531441-1)}{8}[/tex]
S = [tex]\frac{23.(531440)}{8}[/tex] = 23 × 66430
S = 1,527,890
