Respuesta :
Given system of equation:
y+4=x² Equation 1
y-x=2 Equation 2
Isolate y from equation 2.
y=x+2 Substitute value of y in equation 1.
x+2+4=x²
x+6=x²
x²-x-6=0
Solve for x.
x²-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x-3=0 or x=3
and
x+2=0 or x=-2
Substitute value of x in y=x+2
y=-2+2=0
and
y=3+2=5
So solutions are (-2,0) and (3,5)
Answer: (-2,0) and (3,5)
y+4=x² Equation 1
y-x=2 Equation 2
Isolate y from equation 2.
y=x+2 Substitute value of y in equation 1.
x+2+4=x²
x+6=x²
x²-x-6=0
Solve for x.
x²-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x-3=0 or x=3
and
x+2=0 or x=-2
Substitute value of x in y=x+2
y=-2+2=0
and
y=3+2=5
So solutions are (-2,0) and (3,5)
Answer: (-2,0) and (3,5)
Answer:
[tex](-2,0)[/tex] and [tex](3,5)[/tex]
Step-by-step explanation:
we have
[tex]y+4=x^{2}[/tex] -----> equation A
Is a vertical parabola open upward
[tex]y-x=2[/tex] ----> equation B
Is the equation of a line
we know that
The solution of the system of equations is the intersection point both graphs
Using a graphing tool
The intersection points are [tex](-2,0)[/tex] and [tex](3,5)[/tex]
see the attached figure
