Respuesta :

mathmate
For a binomial distribution, the variance is
[tex]\sigma^2=npq=np(1-p)=10*0.7*0.3=2.1 [/tex]
[tex]\sigma=standard\,deviation=\sqrt{2.1}=1.449[/tex] (to 3 decimal places)

The standard deviation for the given binomial distribution is 1.449.

What is binomial distribution?

A binomial random variable is the number of successes x in n repeated trials of a binomial experiment. The probability distribution of a binomial random variable is called a binomial distribution.

Formula for the calculation of standard deviation

σ = [tex]\sqrt{nP(1 -P)}[/tex]

where,

σ is the standard deviation

n is the number of trials in the binomial experiment.

P is the probability of success on an individual.

According to the given question we have,

The number of trials in the binomial experiment, n = 10

The probability of success on an individual, p = 0.70

Therefore, the standard deviation is given by

σ = [tex]\sqrt{10(0.70)(1 -0.70)} = \sqrt{7(0.3)}=\sqrt{2.1} =1.449[/tex]

Hence, the standard deviation for the given binomial distribution is 1.449.

Learn more about the binomial distribution here:

https://brainly.com/question/14565246

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