Answer : The average speed of the sprinter is, 34.95 Km/hr
Solution :
Average velocity : It is defined as the distance traveled by the time taken.
Formula used for average velocity :
[tex]v_{av}=\frac{d}{t}[/tex]
where,
[tex]v_{av}[/tex] = average velocity
d = distance traveled = 200 m
t = time taken = 20.6 s
Now put all the given values in the above formula, we get the average velocity of the sprinter.
[tex]v_{av}=\frac{200m}{20.6s}\times \frac{3600}{1000}=34.95Km/hr[/tex]
conversion :
(1 Km = 1000m)
(1 hr = 3600 s)
Therefore, the average speed of the sprinter is, 34.95 Km/hr
The average speed of the sprinter in kilometers per hour is about 35.0 km/h
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
This problem is about Kinematics.
We will solve it in the following way
Given:
distance traveled = d = 200.0 m
time taken = t = 20.6 s
Unknown:
average speed = v = ?
Solution:
[tex]v = \frac{d}{t}[/tex]
[tex]v = \frac{200}{20.6}[/tex]
[tex]v = \frac{1000}{103} ~ m/s[/tex]
Next we will change the units of this speed into km/h.
[tex]v = \frac{1000}{103} \times \frac{3600}{1000} ~ km/h[/tex]
[tex]v = \frac{3600}{103}~ km/h[/tex]
[tex]v \approx 35.0 ~ km/h[/tex]
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
