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Answer is: name of Sn(SO₄)₂ is tin(IV) sulfate or stannic sulfate.
Major oxidation numbers for tin are +2 and +4 (group 14 of the periodic table). In this chemical compond tin has oxidation number +4, besause sulfate has oxidation number -2 (2·(-2) = -4). Compound has neutral charge and it is moderately water and acid soluble.

Answer: The name of the given compound is tin (IV) sulfate.

Explanation:

The given compound is formed by the combination of tin ions and sulfate ions. It is an ionic compound.

The nomenclature of ionic compounds is given by:

  1. Positive ion is written first.
  2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
  3. In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.

In the given compound, tin is present in +4 oxidation state.

Hence, the name of the given compound is tin (IV) sulfate

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