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Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?

Respuesta :

skyluke89
The total force applied by the three people is:
[tex]F=30 N+20 N+10 N=60 N[/tex]
This force is pushing toward the direction of the motion, while the  frictional force [tex]F_f[/tex] points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
[tex]F-F_f = ma[/tex]
We know the mass of the block, m=500 kg, and the acceleration, [tex]a=0.02 m/s^2[/tex], so we can find the friction:
[tex]F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N[/tex]

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