Respuesta :

when a change in PH = 10^-ΔPH
so the change = 10^-3.2
change depends on two factor 0.00063 (10^-3.2)and factor 1585 (10^3.2)depending on the way which the change goes.if PH change from PH=0 to PH= 3.2 so the change is decreasing from concentration from 1 mol to 0.00063 and if PH change from PH = 3.2 to PH=0 so the change is increasing by a factor of 1585.

The [H+] change for pH change of 3.20 = 1584.89.

What is pH?

pH is potential hydrogen. pH is a scale for measurement of acid and base.

The pH equation is

[tex]\rm pH = -log[H^+][/tex]

[tex]\rm -pH = log[H^+]\\[/tex]

[tex]\rm [H^+] = 10^-^p^H[/tex]

Now, assume the initial pHo is x

The pH after change would be  x + 3.20

Calculating the pH after change

[tex]\rm \Delta [H^+] = \dfrac{10^-^p^H^\circ}{10^-^p^H^f} \\\\\\\Delta [H^+]= \dfrac{10^-^x}{10^-^(^x^+^3^.^2^0^)} \\\\\\\Delta [H^+]= 1584.89[/tex]

Thus, the pH change is 1584.89.

Learn more about pH, here:

https://brainly.com/question/15289741