The cylinder shown has a volume of 54π cm3. In a similar cylinder, the dimensions have been doubled. What is the ratio of the volumes (small to large)?

Respuesta :

The answer to the problem is 1:8

Answer:

1: 8

Step-by-step explanation:

Volume of a cylinder(V) is given by:

[tex]V = \pi r^2h[/tex]

where,

r is the radius and h is the height of the cylinder.

As per the statement:

Let V and V' be the volume of small cylinder and large cylinder.

The small cylinder has a volume of 54π cm^3.

⇒[tex]V =54 \pi cm^3= pi r^2h[/tex]                ....[1]

It is also given:

In a similar cylinder, the dimensions have been doubled

[tex]r' = 2r[/tex] and [tex]h' = 2h[/tex]

then, volume for large cylinder we get;

[tex]V' = \pi (2r)^2(2h) = 8 \pi r^2h[/tex]

⇒[tex]V' = 8V[/tex]

⇒[tex]\frac{V}{V'} = \frac{1}{8}[/tex]

⇒V : V' = 1 : 8

Therefore, the ratio of the volumes (small to large) is, 1: 8