Respuesta :
[tex]3x \times 2 = y[/tex]
this is what I would come up with because.
y=the number of people infected
x=the number of days that have passed
Answer:
[tex]a_{n}=(2)^{n-1}[/tex]
Step-by-step explanation:
The given problem models a geometric sequence, because each day is double than the day before.
So, if [tex]a_{1}[/tex] represents the first day, [tex]r=2[/tex] represents the increasing reason and [tex]a_{n}[/tex] represents the day [tex]n[/tex], or the final day you can say.
Using all these elements, the sequence can be modelled as
[tex]a_{n}=a_{1}r^{n-1}\\ a_{n}=1(2)^{n-1}\\a_{n}=(2)^{n-1}[/tex]
Where the first day is 1.
For example, after 20 days, that is, [tex]n = 20[/tex], the number of infected people would be
[tex]a_{n}=(2)^{n-1}\\a_{20}=(2)^{20-1}=(2)^{19}[/tex]
Therefore, the expression that models this problem is
[tex]a_{n}=(2)^{n-1}[/tex]
