Lets look for the factors of 153 that are 4 or greater, and 11 or less. first step is to solve for the prime factors.
153
/ \
9 17
/ \ /
3 3 17
So the prime factors of 153 are 3,3, and 17. From this, we now look for two or more numbers among the prime factors that have a product thats 4 or greater, and 11 or less.
3*3=9
4≤9≥11
So the toothpicks can be divided into 9 bags with none left over.
