Part complete the first-order reaction, 2 n2o(g) → 2 n2(g) + o2(g), has a rate constant equal to 0.76 s-1 at 1000 k. how long will it take for the concentration of n2o to decrease to 32 % of its initial concentration?
The time taken for the concentration of N2O to decrease to 32% of its initial concentration is calculated as follows In(A1/A0)=-Kt A1= final concentration = 32/100=0.32 A0= initial concentration =100/1000=1 K= constant= 0.76 per sec
time is therefore calculated as follows In(0.32/1)= -0.76 t -1.1394 =-0.76t divide both sid3es by -0.76 t is therefore= 1.5 s